MenuWithTitle.GetShowLabel Property
Definition
Important
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getShowLabel, this property is only available in Office 2010 and later.
Represents the following attribute in the schema: getShowLabel
[DocumentFormat.OpenXml.SchemaAttr(0, "getShowLabel")]
public DocumentFormat.OpenXml.StringValue GetShowLabel { get; set; }
public DocumentFormat.OpenXml.StringValue GetShowLabel { get; set; }
[DocumentFormat.OpenXml.SchemaAttr(0, "getShowLabel")]
public DocumentFormat.OpenXml.StringValue? GetShowLabel { get; set; }
[DocumentFormat.OpenXml.SchemaAttr("getShowLabel")]
public DocumentFormat.OpenXml.StringValue? GetShowLabel { get; set; }
public DocumentFormat.OpenXml.StringValue? GetShowLabel { get; set; }
member this.GetShowLabel : DocumentFormat.OpenXml.StringValue with get, set
[<DocumentFormat.OpenXml.SchemaAttr(0, "getShowLabel")>]
member this.GetShowLabel : DocumentFormat.OpenXml.StringValue with get, set
[<DocumentFormat.OpenXml.SchemaAttr("getShowLabel")>]
member this.GetShowLabel : DocumentFormat.OpenXml.StringValue with get, set
Public Property GetShowLabel As StringValue
Property Value
- Attributes