XmlChoiceIdentifierAttribute コンストラクタ ()

[アーティクル]
08/14/2007

XmlChoiceIdentifierAttribute クラスの新しいインスタンスを初期化します。

名前空間: System.Xml.Serialization
アセンブリ: System.Xml (system.xml.dll 内)

構文

'宣言
Public Sub New
'使用
Dim instance As New XmlChoiceIdentifierAttribute

public XmlChoiceIdentifierAttribute ()

public:
XmlChoiceIdentifierAttribute ()

public XmlChoiceIdentifierAttribute ()

public function XmlChoiceIdentifierAttribute ()

使用例

MyChoice と ManyChoices という 2 つのフィールドを含んでいる Choices という名前のクラスをシリアル化する例を次に示します。各フィールドに XmlChoiceIdentifierAttribute が適用されており、これらのフィールドは、MemberName プロパティを使用して、それぞれのメンバの値を検出するための列挙体を取得または設定する別のクラスメンバを指定しています。MyChoice フィールドには、対応する列挙体メンバが EnumType フィールド内に存在している単一の値を設定できます。ManyChoices フィールドは、オブジェクトの配列を返します。ChoiceArray フィールドは、列挙値の配列を返します。ManyChoices フィールドの各配列メンバに対応するメンバが、ChoiceArray フィールドによって返される配列の中に見つかります。

Imports System
Imports System.Xml
Imports System.Xml.Serialization
Imports System.IO

Public Class Choices
   ' The MyChoice field can be set to any one of 
   ' the types below. 
   <XmlChoiceIdentifier("EnumType"), _
   XmlElement("Word", GetType(String)), _
   XmlElement("Number", GetType(Integer)), _
   XmlElement("DecimalNumber", GetType(double))> _
   Public MyChoice As Object 

   ' Don't serialize this field. The EnumType field
   ' contains the enumeration value that corresponds
   ' to the MyChoice field value.
   <XmlIgnore> _
   Public EnumType As ItemChoiceType 

   'The ManyChoices field can contain an array
   ' of choices. Each choice must be matched to
   ' an array item in the ChoiceArray field.
   <XmlChoiceIdentifier("ChoiceArray"), _
   XmlElement("Item", GetType(string)), _
   XmlElement("Amount", GetType(Integer)), _
   XmlElement("Temp", GetType(double))> _
   Public ManyChoices() As Object

   ' TheChoiceArray field contains the enumeration
   ' values, one for each item in the ManyChoices array.
   <XmlIgnore> _
   Public ChoiceArray() As MoreChoices
End Class

<XmlType(IncludeInSchema:=false)> _
Public Enum ItemChoiceType
   None
   Word 
   Number
   DecimalNumber
End Enum

<XmlType(IncludeInSchema:=false)> _
Public Enum MoreChoices
   None
   Item
   Amount
   Temp
End Enum

Public Class Test
   Shared Sub Main()
      Dim t  As Test = New Test()
      t.SerializeObject("Choices.xml")
      t.DeserializeObject("Choices.xml")
   End Sub

   private Sub SerializeObject(filename As string)
      Dim mySerializer As XmlSerializer = _
      New XmlSerializer(GetType(Choices))
      Dim writer As TextWriter = New StreamWriter(filename)
      Dim myChoices As Choices = New Choices()

      ' Set the MyChoice field to a string. Set the
      ' EnumType to Word.
      myChoices.MyChoice= "Book"
      myChoices.EnumType = ItemChoiceType.Word

      ' Populate an object array with three items, one
      ' of each enumeration type. Set the array to the 
      ' ManyChoices field.
      Dim strChoices () As Object = New object(){"Food",  5, 98.6}
      myChoices.ManyChoices=strChoices

      ' For each item in the ManyChoices array, add an
      ' enumeration value.
      Dim itmChoices () As MoreChoices = New MoreChoices() _
      {MoreChoices.Item, _
      MoreChoices.Amount, _
      MoreChoices.Temp}
      myChoices.ChoiceArray=itmChoices
      
      mySerializer.Serialize(writer, myChoices)
      writer.Close()
   End Sub

   private Sub DeserializeObject(filename As string)
      Dim ser As XmlSerializer = New XmlSerializer(GetType(Choices))
      

      ' A FileStream is needed to read the XML document.
      Dim fs As FileStream = New FileStream(filename, FileMode.Open)
      
      Dim myChoices As Choices = CType(ser.Deserialize(fs), Choices)

      fs.Close()

      ' Disambiguate the MyChoice value Imports the enumeration.
      if myChoices.EnumType = ItemChoiceType.Word Then
           Console.WriteLine("Word: " & _
           myChoices.MyChoice.ToString())
        
      else if myChoices.EnumType = ItemChoiceType.Number Then 
           Console.WriteLine("Number: " & _
            myChoices.MyChoice.ToString())
        
      else if myChoices.EnumType = ItemChoiceType.DecimalNumber Then
         Console.WriteLine("DecimalNumber: " & _
            myChoices.MyChoice.ToString())
        End If

      ' Disambiguate the ManyChoices values Imports the enumerations.
      Dim i As Integer
      for i = 0 to myChoices.ManyChoices.Length -1
      if myChoices.ChoiceArray(i) = MoreChoices.Item Then
        Console.WriteLine("Item: " +  _
        myChoices.ManyChoices(i).ToString())
      else if myChoices.ChoiceArray(i) = MoreChoices.Amount Then
        Console.WriteLine("Amount: " + _
        myChoices.ManyChoices(i).ToString())
      else if (myChoices.ChoiceArray(i) = MoreChoices.Temp)
        Console.WriteLine("Temp: " + _
        myChoices.ManyChoices(i).ToString())
        End If
        Next i
      
   End Sub
End Class

using System;
using System.Xml;
using System.Xml.Serialization;
using System.IO;

public class Choices{
   // The MyChoice field can be set to any one of 
   // the types below. 
   [XmlChoiceIdentifier("EnumType")]
   [XmlElement("Word", typeof(string))]
   [XmlElement("Number", typeof(int))]
   [XmlElement("DecimalNumber", typeof(double))]
   public object MyChoice;

   // Don't serialize this field. The EnumType field
   // contains the enumeration value that corresponds
   // to the MyChoice field value.
   [XmlIgnore]
   public ItemChoiceType EnumType;

   // The ManyChoices field can contain an array
   // of choices. Each choice must be matched to
   // an array item in the ChoiceArray field.
   [XmlChoiceIdentifier("ChoiceArray")]
   [XmlElement("Item", typeof(string))]
   [XmlElement("Amount", typeof(int))]
   [XmlElement("Temp", typeof(double))]
   public object[] ManyChoices;

   // TheChoiceArray field contains the enumeration
   // values, one for each item in the ManyChoices array.
   [XmlIgnore]
   public MoreChoices[] ChoiceArray;
}

[XmlType(IncludeInSchema=false)]
public enum ItemChoiceType{
   None,
   Word, 
   Number,
   DecimalNumber
}

public enum MoreChoices{
   None,
   Item,
   Amount,
   Temp
}

public class Test{
   static void Main(){
      Test t = new Test();
      t.SerializeObject("Choices.xml");
      t.DeserializeObject("Choices.xml");
   }

   private void SerializeObject(string filename){
      XmlSerializer mySerializer = 
      new XmlSerializer(typeof(Choices));
      TextWriter writer = new StreamWriter(filename);
      Choices myChoices = new Choices();

      // Set the MyChoice field to a string. Set the
      // EnumType to Word.
      myChoices.MyChoice= "Book";
      myChoices.EnumType = ItemChoiceType.Word;

      // Populate an object array with three items, one
      // of each enumeration type. Set the array to the 
      // ManyChoices field.
      object[] strChoices = new object[]{"Food",  5, 98.6};
      myChoices.ManyChoices=strChoices;

      // For each item in the ManyChoices array, add an
      // enumeration value.
      MoreChoices[] itmChoices = new MoreChoices[]
      {MoreChoices.Item, 
      MoreChoices.Amount,
      MoreChoices.Temp};
      myChoices.ChoiceArray=itmChoices;
      
      mySerializer.Serialize(writer, myChoices);
      writer.Close();
   }

   private void DeserializeObject(string filename){
      XmlSerializer ser = new XmlSerializer(typeof(Choices));

      // A FileStream is needed to read the XML document.
      FileStream fs = new FileStream(filename, FileMode.Open);
      Choices myChoices = (Choices)
      ser.Deserialize(fs);
      fs.Close();

      // Disambiguate the MyChoice value using the enumeration.
      if(myChoices.EnumType == ItemChoiceType.Word){
           Console.WriteLine("Word: " +  
            myChoices.MyChoice.ToString());
        }
      else if(myChoices.EnumType == ItemChoiceType.Number){
           Console.WriteLine("Number: " +
            myChoices.MyChoice.ToString());
        }
      else if(myChoices.EnumType == ItemChoiceType.DecimalNumber){
           Console.WriteLine("DecimalNumber: " +
            myChoices.MyChoice.ToString());
        }

      // Disambiguate the ManyChoices values using the enumerations.
      for(int i = 0; i<myChoices.ManyChoices.Length; i++){
      if(myChoices.ChoiceArray[i] == MoreChoices.Item)
        Console.WriteLine("Item: " + (string) myChoices.ManyChoices[i]);
      else if(myChoices.ChoiceArray[i] == MoreChoices.Amount)
        Console.WriteLine("Amount: " + myChoices.ManyChoices[i].ToString());
      if(myChoices.ChoiceArray[i] == MoreChoices.Temp)
        Console.WriteLine("Temp: " + (string) myChoices.ManyChoices[i].ToString());
        }
      
   }
}

#using <System.dll>
#using <System.xml.dll>

using namespace System;
using namespace System::Xml;
using namespace System::Xml::Serialization;
using namespace System::IO;

[XmlType(IncludeInSchema=false)]

public enum class ItemChoiceType
{
   None, Word, Number, DecimalNumber
};

public enum class MoreChoices
{
   None, Item, Amount, Temp
};

public ref class Choices
{
public:

   // The MyChoice field can be set to any one of 
   // the types below. 

   [XmlChoiceIdentifier("EnumType")]
   [XmlElement("Word",String::typeid)]
   [XmlElement("Number",Int32::typeid)]
   [XmlElement("DecimalNumber",Double::typeid)]
   Object^ MyChoice;

   // Don't serialize this field. The EnumType field
   // contains the enumeration value that corresponds
   // to the MyChoice field value.

   [XmlIgnore]
   ItemChoiceType EnumType;

   // The ManyChoices field can contain an array
   // of choices. Each choice must be matched to
   // an array item in the ChoiceArray field.

   [XmlChoiceIdentifier("ChoiceArray")]
   [XmlElement("Item",String::typeid)]
   [XmlElement("Amount",Int32::typeid)]
   [XmlElement("Temp",Double::typeid)]
   array<Object^>^ManyChoices;

   // TheChoiceArray field contains the enumeration
   // values, one for each item in the ManyChoices array.

   [XmlIgnore]
   array<MoreChoices>^ChoiceArray;
};

void SerializeObject( String^ filename );
void DeserializeObject( String^ filename );
int main()
{
   SerializeObject( "Choices.xml" );
   DeserializeObject( "Choices.xml" );
}

void SerializeObject( String^ filename )
{
   XmlSerializer^ mySerializer = gcnew XmlSerializer( Choices::typeid );
   TextWriter^ writer = gcnew StreamWriter( filename );
   Choices^ myChoices = gcnew Choices;

   // Set the MyChoice field to a string. Set the
   // EnumType to Word.
   myChoices->MyChoice = "Book";
   myChoices->EnumType = ItemChoiceType::Word;

   // Populate an object array with three items, one
   // of each enumeration type. Set the array to the 
   // ManyChoices field.
   array<Object^>^strChoices = {"Food",5,98.6};
   myChoices->ManyChoices = strChoices;

   // For each item in the ManyChoices array, add an
   // enumeration value.
   array<MoreChoices>^ itmChoices = {MoreChoices::Item,MoreChoices::Amount,MoreChoices::Temp};
   myChoices->ChoiceArray = itmChoices;
   mySerializer->Serialize( writer, myChoices );
   writer->Close();
}

void DeserializeObject( String^ filename )
{
   XmlSerializer^ ser = gcnew XmlSerializer( Choices::typeid );

   // A FileStream is needed to read the XML document.
   FileStream^ fs = gcnew FileStream( filename,FileMode::Open );
   Choices^ myChoices = safe_cast<Choices^>(ser->Deserialize( fs ));
   fs->Close();

   // Disambiguate the MyChoice value using the enumeration.
   if ( myChoices->EnumType == ItemChoiceType::Word )
   {
      Console::WriteLine( "Word: {0}", myChoices->MyChoice->ToString() );
   }
   else
   if ( myChoices->EnumType == ItemChoiceType::Number )
   {
      Console::WriteLine( "Number: {0}", myChoices->MyChoice->ToString() );
   }
   else
   if ( myChoices->EnumType == ItemChoiceType::DecimalNumber )
   {
      Console::WriteLine( "DecimalNumber: {0}", myChoices->MyChoice->ToString() );
   }

   // Disambiguate the ManyChoices values using the enumerations.
   for ( int i = 0; i < myChoices->ManyChoices->Length; i++ )
   {
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Item )
            Console::WriteLine( "Item: {0}", myChoices->ManyChoices[ i ] );
      else
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Amount )
            Console::WriteLine( "Amount: ", myChoices->ManyChoices[ i ]->ToString() );
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Temp )
            Console::WriteLine( "Temp: {0}", myChoices->ManyChoices[ i ]->ToString() );
   }
}

import System.*;
import System.Xml.*;
import System.Xml.Serialization.*;
import System.IO.*;
public class Choices
{
    // The myChoice field can be set to any one of 
    // the types below. 
    /** @attribute XmlElement("word", String.class)
     */
    /** @attribute XmlElement("Number", int.class)
     */
    /** @attribute XmlElement("DecimalNumber", double.class)
     */
    public Object myChoice;

    // Don't serialize this field. The EnumType field
    // contains the enumeration value that corresponds
    // to the myChoice field value.
    public int enumType;

    // The manyChoices field can contain an array
    // of choices. Each choice must be matched to
    // an array item in the choiceArray field.
    /** @attribute XmlElement("Item", String.class)
     */
    /** @attribute XmlElement("amount", int.class)
     */
    /** @attribute XmlElement("temp", double.class)
     */
    public Object manyChoices[];

    // ThechoiceArray field contains the enumeration
    // values, one for each item in the manyChoices array.
    public int choiceArray[];
} //Choices

/** @attribute XmlType(IncludeInSchema = false)
 */
public class ItemChoiceType
{
    public static final int none = 0;
    public static final int word = 1;
    public static final int number = 2;
    public static final int decimalNumber = 3;
} //ItemChoiceType

public class MoreChoices
{
    public static final int none = 0;
    public static final int item = 1;
    public static final int amount = 2;
    public static final int temp = 3;
} //MoreChoices

public class Test
{
    public static void main(String[] args)
    {
        Test t = new Test();
        t.SerializeObject("Choices.xml");
        t.DeserializeObject("Choices.xml");
    } //main

    private void SerializeObject(String fileName)
    {
        XmlSerializer mySerializer = new XmlSerializer(Choices.class.ToType());
        TextWriter writer = new StreamWriter(fileName);
        Choices myChoices = new Choices();
        // Set the myChoice field to a string. Set the
        // enumType to word.
        myChoices.myChoice = "Book";
        myChoices.enumType = ItemChoiceType.word;
        // Populate an object array with three items, one
        // of each enumeration type. Set the array to the 
        // manyChoices field.
        Object strChoices[] = new Object[] { "Food", (Int32)5,
            (System.Double)98.6 };
        myChoices.manyChoices = strChoices;
        // For each item in the manyChoices array, add an
        // enumeration value.
        int itmChoices[] = new int[] {
            MoreChoices.item, MoreChoices.amount, MoreChoices.temp
        };

        myChoices.choiceArray = new int[itmChoices.get_Length()];
        itmChoices.CopyTo(myChoices.choiceArray, 0);

        //myChoices.choiceArray = itmChoices;
        mySerializer.Serialize(writer, myChoices);
        writer.Close();
    } //SerializeObject

    private void DeserializeObject(String fileName)
    {
        XmlSerializer ser = new XmlSerializer(Choices.class.ToType());
        // A FileStream is needed to read the XML document.
        FileStream fs = new FileStream(fileName, FileMode.Open);
        Choices myChoices = (Choices)ser.Deserialize(fs);
        fs.Close();
        // Disambiguate the myChoice value using the enumeration.
        if (myChoices.enumType == ItemChoiceType.word) {
            Console.WriteLine("Word: " + myChoices.myChoice.ToString());
        }
        else {
            if (myChoices.enumType == ItemChoiceType.number) {
                Console.WriteLine("Number: " + myChoices.myChoice.ToString());
            }
            else {
                if (myChoices.enumType == ItemChoiceType.decimalNumber) {
                    Console.WriteLine("DecimalNumber: " +
                        myChoices.myChoice.ToString());
                }
            }
        }
        // Disambiguate the manyChoices values using the enumerations.
        for (int i = 0; i < myChoices.manyChoices.get_Length(); i++) {
            if (System.Convert.ToInt32(myChoices.choiceArray.get_Item(i)) ==
                MoreChoices.item) {
                Console.WriteLine("Item: " 
                    + (String)(myChoices.manyChoices.get_Item(i)));
            }
            else {
                if (System.Convert.ToInt32(myChoices.choiceArray.
                    get_Item(i)) == MoreChoices.amount) {
                    Console.WriteLine("Amount: " +
                        myChoices.manyChoices.get_Item(i).ToString());
                }
            }
            if (System.Convert.ToInt32(myChoices.choiceArray.
                get_Item(i)) == MoreChoices.temp) {
                Console.WriteLine("Temp: " + (String)(
                    myChoices.manyChoices.get_Item(i).ToString()));
            }
        }
    } //DeserializeObject 
} //Test

プラットフォーム

Windows 98, Windows 2000 SP4, Windows CE, Windows Millennium Edition, Windows Mobile for Pocket PC, Windows Mobile for Smartphone, Windows Server 2003, Windows XP Media Center Edition, Windows XP Professional x64 Edition, Windows XP SP2, Windows XP Starter Edition

開発プラットフォームの中には、.NET Framework によってサポートされていないバージョンがあります。サポートされているバージョンについては、「システム要件」を参照してください。

次の方法で共有

XmlChoiceIdentifierAttribute コンストラクタ ()

構文

使用例

プラットフォーム

バージョン情報

.NET Framework

.NET Compact Framework

参照

関連項目

その他のリソース