Errorlevel and Findstr

ErrorLevel is not %ERRORLEVEL% . This is probably the first one you should read.

Next is the usage of the ERRORLEVEL statement. https://support.microsoft.com/kb/69576

 

The following table shows the effect of statement when writing your batch scriipt.

Statement	Algebraic Equivalent.
IF ERRORLEVEL 5 ...	IF E = 5 OR E > 5 THEN ...
IF NOT ERRORLEVEL 6	IF E < 6 THEN ...

Here is a sample using findstr and error level. Findstr returns 0 if it successfully finds any occurrence.

 findstr -sip Failed log.txt > NULL
IF NOT ERRORLEVEL 1 ( 
    echo Found.
) else (
    echo Not Found.
)

Comments

• Anonymous
  July 07, 2013
  Using your method this returns true that it finds Windows 7 on Windows 8 and Windows 2008 OS's? Can you explain where I am going wrong? reg query "HKEY_LOCAL_MACHINESOFTWAREMicrosoftWindows NTCurrentVersion" /v ProductName | findstr /i "Windows 7 professional" >NUL IF NOT ERRORLEVEL 1 (    echo I found Windows 7. ) else (    echo I did not find Windows 7. ) pause

• Anonymous
  July 09, 2013
  Scott findstr needs /c:"..." for an exact match. Change the script to this worked for me . reg query "HKEY_LOCAL_MACHINESOFTWAREMicrosoftWindows NTCurrentVersion" /v ProductName | findstr /c:"Windows 7" >NUL IF NOT ERRORLEVEL 1 ( echo I found Windows 7. ) else ( echo I did not find Windows 7. )