merge (STL Samples)
Viene illustrato come utilizzare unione Funzione della libreria di modelli standard (STL) in Visual C++.
template<
class InputIterator1,
class InputIterator2,
class OutputIterator
> inline
OutputIterator merge(
InputIterator1 First1,
InputIterator1 Last1,
InputIterator2 First2,
InputIterator2 Last2,
OutputIterator Result
)
Note
[!NOTA]
La classe/nomi di parametro nel prototipo non corrisponde alla versione nel file di intestazione.alcuni sono stati modificati per migliorare la leggibilità.
unione l'algoritmo unisce due sequenze ordinate: [First1.Last1) e [First2.Last2) in una sola sequenza ordinata che inizia a risultato.questa versione presuppone che gli intervalli [First1.Last1) e [First2.Last2vengono ordinati utilizzando operator<.Se entrambi gli intervalli contenenti valori uguali, il valore del primo intervallo verrà archiviato per primo.Il risultato dell'unione degli intervalli si sovrappongono è definito.
Esempio
// merge.cpp
// compile with: /EHsc
//
// Functions:
// merge : Merge two sorted sequences
// into a single sorted list.
// disable warning C4786: symbol greater than 255 character,
// okay to ignore
#pragma warning(disable: 4786)
#include <iostream>
#include <algorithm>
#include <vector>
#include <list>
#include <deque>
using namespace std ;
int main()
{
const int MAX_ELEMENTS = 8 ;
// Define a template class vector of int
typedef vector<int> IntVector ;
//Define an iterator for template class vector of ints
typedef IntVector::iterator IntVectorIt ;
IntVector NumbersVector(MAX_ELEMENTS) ;
IntVectorIt startv, endv, itv ;
// Define a template class list of int
typedef list<int> IntList ;
//Define an iterator for template class list of ints
typedef IntList::iterator IntListIt ;
IntList NumbersList ;
IntListIt first, last, itl ;
// Define a template class deque of int
typedef deque<int> IntDeque ;
//Define an iterator for template class deque of ints
typedef IntDeque::iterator IntDequeIt ;
IntDeque NumbersDeque(2 * MAX_ELEMENTS) ;
IntDequeIt itd ;
// Initialize vector NumbersVector
NumbersVector[0] = 4 ;
NumbersVector[1] = 10;
NumbersVector[2] = 70 ;
NumbersVector[3] = 10 ;
NumbersVector[4] = 30 ;
NumbersVector[5] = 69 ;
NumbersVector[6] = 96 ;
NumbersVector[7] = 100;
startv = NumbersVector.begin() ; // location of first
// element of NumbersVector
endv = NumbersVector.end() ; // one past the location
// last element of NumbersVector
// sort NumbersVector, merge requires the sequences
// to be sorted
sort(startv, endv) ;
// print content of NumbersVector
cout << "NumbersVector { " ;
for(itv = startv; itv != endv; itv++)
cout << *itv << " " ;
cout << " }\n" << endl ;
// Initialize vector NumbersList
for(int i = 0; i < MAX_ELEMENTS; i++)
NumbersList.push_back(i) ;
first = NumbersList.begin() ; // location of first
// element of NumbersList
last = NumbersList.end() ; // one past the location
// last element of NumbersList
// print content of NumbersList
cout << "NumbersList { " ;
for(itl = first; itl != last; itl++)
cout << *itl << " " ;
cout << " }\n" << endl ;
// merge the elements of NumbersVector
// and NumbersList and place the
// results in NumbersDeque
merge(startv, endv, first, last, NumbersDeque.begin()) ;
cout << "After calling merge\n" << endl ;
// print content of NumbersDeque
cout << "NumbersDeque { " ;
for(itd = NumbersDeque.begin();
itd != NumbersDeque.end(); itd++)
cout << *itd << " " ;
cout << " }\n" << endl ;
}
Output
NumbersVector { 4 10 10 30 69 70 96 100 }
NumbersList { 0 1 2 3 4 5 6 7 }
After calling merge
NumbersDeque { 0 1 2 3 4 4 5 6 7 10 10 30 69 70 96 100 }
Requisiti
intestazione: <algoritmo>