isgraph

Verifica se un elemento in impostazioni locali è un carattere di punteggiatura o alfanumerico.

template<Class CharType>
   bool isgraph(
      CharType _Ch, 
      const locale& _Loc
   )

Parametri

• _Ch
  l'elemento da testare.

• _Loc
  Le impostazioni locali che contengono l'elemento da testare.

Valore restituito

true se l'elemento è verificato un alfanumerico o un carattere di punteggiatura, false caso contrario.

Note

La funzione di modello restituisce use_facet<tipo C<char> > (_Loc).viene(ctype< >_double_colon_graph, _Chdichar).

Esempio

// locale_is_graph.cpp
// compile with: /EHsc
#include <locale>
#include <iostream>

using namespace std;

int main( )
{
   locale loc ( "German_Germany" );
   bool result1 = isgraph ( 'L', loc );
   bool result2 = isgraph ( '\t', loc );
   bool result3 = isgraph ( '.', loc );

   if ( result1 )
      cout << "The character 'L' in the locale is\n "
           << "an alphanumeric or punctuation character." << endl;
   else
      cout << "The character 'L' in the locale is\n "
           << " not an alphanumeric or punctuation character." << endl;

   if ( result2 )
      cout << "The character 'backslash-t' in the locale is\n "
           << "an alphanumeric or punctuation character." << endl;
   else
      cout << "The character 'backslash-t' in the locale is\n "
           << "not an alphanumeric or punctuation character." << endl;

   if ( result3 )
      cout << "The character '.' in the locale is\n "
           << "an alphanumeric or punctuation character." << endl;
   else
      cout << "The character '.' in the locale is\n "
           << " not an alphanumeric or punctuation character." << endl;
}

Output

The character 'L' in the locale is
 an alphanumeric or punctuation character.
The character 'backslash-t' in the locale is
 not an alphanumeric or punctuation character.
The character '.' in the locale is
 an alphanumeric or punctuation character.

Requisiti

intestazione: <locale>

Spazio dei nomi: deviazione standard