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Metodo UserDefinedType (String, String)

Returns an object that represents the specified type with the specified schema.

Spazio dei nomi  Microsoft.SqlServer.Management.Smo
Assembly:  Microsoft.SqlServer.Smo (in Microsoft.SqlServer.Smo.dll)

Sintassi

'Dichiarazione
Public Shared Function UserDefinedType ( _
    type As String, _
    schema As String _
) As DataType
'Utilizzo
Dim type As String
Dim schema As String
Dim returnValue As DataType

returnValue = DataType.UserDefinedType(type, _
    schema)

public static DataType UserDefinedType(
    string type,
    string schema
)

public:
static DataType^ UserDefinedType(
    String^ type, 
    String^ schema
)

static member UserDefinedType : 
        type:string * 
        schema:string -> DataType 

public static function UserDefinedType(
    type : String, 
    schema : String
) : DataType

Parametri

Valore restituito

Tipo: Microsoft.SqlServer.Management.Smo. . :: . .DataType
A DataType object value.

Esempi

The following code example shows how to create a user-defined type.

C#

Server srv = new Server("(local)");
Database db = srv.Databases["AdventureWorks2008R2"];
Schema schema1 = new Schema(db, "ExampleSchema");
schema1.Create();
UserDefinedType udt = new UserDefinedTableType(db, "udt", "ExampleSchema");
udt.Create();
DataType userType = new DataType(SqlDataType.UserDefinedType, "udt", "ExampleSchema");

Powershell

$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = $srv.Databases.Item("AdventureWorks2008R2")
$schema1 = new-object Microsoft.SqlServer.Management.Smo.Schema($db, "ExampleSchema")
$schema1.Create()
$udt = new-object Microsoft.SqlServer.Management.Smo.UserDefinedType($db, "udt", "ExampleSchema")
$userTable = new-object Microsoft.SqlServer.Management.Smo.DataType([Microsoft.SqlServer.Management.Smo.SqlDataType]::UserDefinedType, "udt", "ExampleSchema")