DatePart Function
Returns the specified part of a given date.
Syntax
DatePart(interval, date[, firstdayofweek[, firstweekofyear]])
Arguments
interval
Required. String expression that is the interval of time you want to return. See Settings section for values.date
Required. Date expression you want to evaluate.firstdayof week
Optional. Constant that specifies the day of the week. If not specified, Sunday is assumed. See Settings section for values.firstweekofyear
Optional. Constant that specifies the first week of the year. If not specified, the first week is assumed to be the week in which January 1 occurs. See Settings section for values.
Settings
The interval argument can have the following values:
Setting |
Description |
|---|---|
yyyy |
Year |
q |
Quarter |
m |
Month |
y |
Day of year |
d |
Day |
w |
Weekday |
ww |
Week of year |
h |
Hour |
n |
Minute |
s |
Second |
The firstdayofweek argument can have the following values:
Constant |
Value |
Description |
|---|---|---|
vbUseSystemDayOfWeek |
0 |
Use National Language Support (NLS) API setting. |
vbSunday |
1 |
Sunday (default) |
vbMonday |
2 |
Monday |
vbTuesday |
3 |
Tuesday |
vbWednesday |
4 |
Wednesday |
vbThursday |
5 |
Thursday |
vbFriday |
6 |
Friday |
vbSaturday |
7 |
Saturday |
The firstweekofyear argument can have the following values:
Constant |
Value |
Description |
|---|---|---|
vbUseSystem |
0 |
Use National Language Support (NLS) API setting. |
vbFirstJan1 |
1 |
Start with the week in which January 1 occurs (default). |
vbFirstFourDays |
2 |
Start with the week that has at least four days in the new year. |
vbFirstFullWeek |
3 |
Start with the first full week of the new year. |
Remarks
You can use the DatePart function to evaluate a date and return a specific interval of time. For example, you might use DatePart to calculate the day of the week or the current hour.
The firstdayofweek argument affects calculations that use the "w" and "ww" interval symbols.
When you use the "w" interval symbol, the weekday value that is returned is 1 for Sunday, 2 for Monday, and so on (unless a firstdayofweek argument is provided).
When you use the "h" interval symbol, the hour that is returned is based on a 24-hour clock, and does not contain A.M. or P.M.
If date is a date literal, the specified year becomes a permanent part of that date. However, if date is enclosed in quotation marks (" "), and you omit the year, the current year is inserted in your code each time the date expression is evaluated. This makes it possible to write code that can be used in different years.
The following example illustrates the use of the DatePart function.
Dim Quarter, DayOfYear, WeekOfYear
Quarter = DatePart("q", Now)
DayOfYear = DatePart("y", Now)
WeekOfYear = DatePart("ww", Now)
Requirements
Change History
Date |
History |
Reason |
|---|---|---|
September 2009 |
Modified the example. |
Customer feedback. |
March 2009 |
Added additional information about the "w" and "h" interval symbols. |
Information enhancement. |
See Also
DateAdd Function
DateDiff Function
Month Function
Hour Function