locale::operator!=

Tests two locales for inequality.

bool operator!=(
    const locale& _Right
) const;

Parameters

• _Right
  One of the locales to be tested for inequality.

Return Value

A Boolean value that is true if the locales are not copies of the same locale; false if the locales are copies of the same locale.

Remarks

Two locales are equal if they are the same locale, if one is a copy of the other, or if they have identical names.

Example

// locale_op_ne.cpp
// compile with: /EHsc
#include <iostream>
#include <string>
#include <locale>

using namespace std;

int main( ) 
{
   locale loc1( "German_Germany" );
   locale loc2( "German_Germany" );
   locale loc3( "English" );

   if ( loc1 != loc2 )
      cout << "locales loc1 (" << loc1.name( )
      << ") and\n loc2 (" << loc2.name( ) << ") are not equal." << endl;
   else
      cout << "locales loc1 (" << loc1.name( )
      << ") and\n loc2 (" << loc2.name( ) << ") are equal." << endl;

   if ( loc1 != loc3 )
      cout << "locales loc1 (" << loc1.name( )
      << ") and\n loc3 (" << loc3.name( ) << ") are not equal." << endl;
   else
      cout << "locales loc1 (" << loc1.name( )
      << ") and\n loc3 (" << loc3.name( ) << ") are equal." << endl;
}

locales loc1 (German_Germany.1252) and
 loc2 (German_Germany.1252) are equal.
locales loc1 (German_Germany.1252) and
 loc3 (English_United States.1252) are not equal.

Requirements

Header: <locale>

Namespace: std

See Also

Reference

locale Class