reverse_iterator::base
Recovers the underlying iterator from its reverse_iterator.
RandomIterator base( ) const;
Return Value
The iterator underlying the reverse_iterator.
Remarks
The identity that relates all reverse iterators to their underlying iterators is:
&*(reverse_iterator ( i ) ) == &*( i – 1 ).
In practice, this means that in the reversed sequence the reverse_iterator will refer to the element one position beyond (to the right of) the element that the iterator had referred to in the original sequence. So if an iterator addressed the element 6 in the sequence (2, 4, 6, 8), then the reverse_iterator will address the element 4 in the reversed sequence (8, 6, 4, 2).
Example
// reverse_iterator_base.cpp
// compile with: /EHsc
#include <iterator>
#include <algorithm>
#include <vector>
#include <iostream>
int main( )
{
using namespace std;
int i;
vector<int> vec;
for ( i = 1 ; i < 6 ; ++i )
{
vec.push_back ( 2 * i );
}
vector <int>::iterator vIter;
cout << "The vector vec is: ( ";
for ( vIter = vec.begin ( ) ; vIter != vec.end ( ); vIter++ )
cout << *vIter << " ";
cout << ")." << endl;
vector <int>::reverse_iterator rvIter;
cout << "The vector vec reversed is: ( ";
for ( rvIter = vec.rbegin( ) ; rvIter != vec.rend( ); rvIter++)
cout << *rvIter << " ";
cout << ")." << endl;
vector <int>::iterator pos, bpos;
pos = find ( vec.begin ( ), vec.end ( ), 6 );
cout << "The iterator pos points to: " << *pos << "." << endl;
typedef reverse_iterator<vector<int>::iterator>::iterator_type it_vec_int_type;
reverse_iterator<it_vec_int_type> rpos ( pos );
cout << "The reverse_iterator rpos points to: " << *rpos
<< "." << endl;
bpos = rpos.base ( );
cout << "The iterator underlying rpos is bpos & it points to: "
<< *bpos << "." << endl;
}
Output
The vector vec is: ( 2 4 6 8 10 ).
The vector vec reversed is: ( 10 8 6 4 2 ).
The iterator pos points to: 6.
The reverse_iterator rpos points to: 4.
The iterator underlying rpos is bpos & it points to: 6.
Requirements
Header: <iterator>
Namespace: std