Exemple qui imprime des parties de document Office Open XML

Cette rubrique montre comment ouvrir un document Office Open XML et accéder à ses parties.

Exemple

L'exemple suivant ouvre un document Office Open XML et imprime la partie document et la partie de style sur la console.

Cet exemple utilise des classes de l'assembly WindowsBase. Il utilise des types dans l'espace de noms System.IO.Packaging.

const string fileName = "SampleDoc.docx";

const string documentRelationshipType =
  "https://schemas.openxmlformats.org/officeDocument/2006/relationships/officeDocument";
const string stylesRelationshipType =
  "https://schemas.openxmlformats.org/officeDocument/2006/relationships/styles";
const string wordmlNamespace =
  "https://schemas.openxmlformats.org/wordprocessingml/2006/main";
XNamespace w = wordmlNamespace;

using (Package wdPackage = Package.Open(fileName, FileMode.Open, FileAccess.Read))
{
    PackageRelationship docPackageRelationship =
      wdPackage.GetRelationshipsByType(documentRelationshipType).FirstOrDefault();
    if (docPackageRelationship != null)
    {
        Uri documentUri = PackUriHelper.ResolvePartUri(new Uri("/", UriKind.Relative),
          docPackageRelationship.TargetUri);
        PackagePart documentPart = wdPackage.GetPart(documentUri);

        //  Load the document XML in the part into an XDocument instance.
        XDocument xdoc = XDocument.Load(XmlReader.Create(documentPart.GetStream()));

        Console.WriteLine("TargetUri:{0}", docPackageRelationship.TargetUri);
        Console.WriteLine("==================================================================");
        Console.WriteLine(xdoc.Root);
        Console.WriteLine();

        //  Find the styles part. There will only be one.
        PackageRelationship styleRelation =
          documentPart.GetRelationshipsByType(stylesRelationshipType).FirstOrDefault();
        if (styleRelation != null)
        {
            Uri styleUri = PackUriHelper.ResolvePartUri(documentUri, styleRelation.TargetUri);
            PackagePart stylePart = wdPackage.GetPart(styleUri);

            //  Load the style XML in the part into an XDocument instance.
            XDocument styleDoc = XDocument.Load(XmlReader.Create(stylePart.GetStream()));

            Console.WriteLine("TargetUri:{0}", styleRelation.TargetUri);
            Console.WriteLine("==================================================================");
            Console.WriteLine(styleDoc.Root);
            Console.WriteLine();
        }
    }
}

Const fileName As String = "SampleDoc.docx"

Const documentRelationshipType As String = _
  "https://schemas.openxmlformats.org/officeDocument/2006/relationships/officeDocument"
Const stylesRelationshipType As String = _
  "https://schemas.openxmlformats.org/officeDocument/2006/relationships/styles"
Const wordmlNamespace As String = _
  "https://schemas.openxmlformats.org/wordprocessingml/2006/main"
Dim w As XNamespace = wordmlNamespace

Using wdPackage As Package = Package.Open(fileName, FileMode.Open, FileAccess.Read)
    Dim docPackageRelationship As PackageRelationship = _
      wdPackage.GetRelationshipsByType(documentRelationshipType).FirstOrDefault()
    If docPackageRelationship IsNot Nothing Then
        Dim documentUri As Uri = PackUriHelper.ResolvePartUri(New Uri("/", UriKind.Relative), _
          docPackageRelationship.TargetUri)
        Dim documentPart As PackagePart = wdPackage.GetPart(documentUri)

        ' Load the document XML in the part into an XDocument instance.
        Dim xdoc As XDocument = XDocument.Load(XmlReader.Create(documentPart.GetStream()))

        Console.WriteLine("TargetUri:{0}", docPackageRelationship.TargetUri)
        Console.WriteLine("==================================================================")
        Console.WriteLine(xdoc.Root)
        Console.WriteLine()

        ' Find the styles part. There will only be one.
        Dim styleRelation As PackageRelationship = _
          documentPart.GetRelationshipsByType(stylesRelationshipType).FirstOrDefault()
        If styleRelation IsNot Nothing Then
            Dim styleUri As Uri = _
              PackUriHelper.ResolvePartUri(documentUri, styleRelation.TargetUri)
            Dim stylePart As PackagePart = wdPackage.GetPart(styleUri)

            ' Load the style XML in the part into an XDocument instance.
            Dim styleDoc As XDocument = XDocument.Load(XmlReader.Create(stylePart.GetStream()))

            Console.WriteLine("TargetUri:{0}", styleRelation.TargetUri)
            Console.WriteLine("==================================================================")
            Console.WriteLine(styleDoc.Root)
            Console.WriteLine()
        End If
    End If
End Using

Voir aussi

Concepts

Détails relatifs aux documents WordprocessingML Office Open XML