CTypeExpressionSyntax.WithType(TypeSyntax) Method
Definition
Important
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Returns a copy of this with the Type property changed to the specified value. Returns this instance if the specified value is the same as the current value.
public:
Microsoft::CodeAnalysis::VisualBasic::Syntax::CTypeExpressionSyntax ^ WithType(Microsoft::CodeAnalysis::VisualBasic::Syntax::TypeSyntax ^ type);public Microsoft.CodeAnalysis.VisualBasic.Syntax.CTypeExpressionSyntax WithType (Microsoft.CodeAnalysis.VisualBasic.Syntax.TypeSyntax type);override this.WithType : Microsoft.CodeAnalysis.VisualBasic.Syntax.TypeSyntax -> Microsoft.CodeAnalysis.VisualBasic.Syntax.CTypeExpressionSyntaxPublic Function WithType (type As TypeSyntax) As CTypeExpressionSyntaxParameters
- type
- TypeSyntax
Returns
Applies to
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