Muokkaa

Jaa

InOutArgument<T>.FromExpression Method

  • Reference

Definition

Namespace:
System.Activities
Assembly:
System.Activities.dll

Initializes and returns a new InOutArgument<T> constructed using the specified Activity<TResult>.

public:
 static System::Activities::InOutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.InOutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.InOutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As InOutArgument(Of T)

Parameters

expression
Activity<Location<T>>

The value of the argument.

Returns

InOutArgument<T>

The new argument.

Applies to