is_fundamental Class
Tests if type is void or arithmetic.
Syntax
template <class Ty>
struct is_fundamental;
Parameters
Ty
The type to query.
Remarks
An instance of the type predicate holds true if the type Ty is a fundamental type, that is, void, an integral type, an floating point type, or a cv-qualified form of one of them, otherwise it holds false.
Example
// std__type_traits__is_fundamental.cpp
// compile with: /EHsc
#include <type_traits>
#include <iostream>
struct trivial
{
int val;
};
int main()
{
std::cout << "is_fundamental<trivial> == " << std::boolalpha
<< std::is_fundamental<trivial>::value << std::endl;
std::cout << "is_fundamental<int> == " << std::boolalpha
<< std::is_fundamental<int>::value << std::endl;
std::cout << "is_fundamental<const float> == " << std::boolalpha
<< std::is_fundamental<const float>::value << std::endl;
std::cout << "is_fundamental<void> == " << std::boolalpha
<< std::is_fundamental<void>::value << std::endl;
return (0);
}
is_fundamental<trivial> == false
is_fundamental<int> == true
is_fundamental<const float> == true
is_fundamental<void> == true
Requirements
Header: <type_traits>
Namespace: std