Set.union(Set, Set) Method

Definition

Namespace:

Microsoft.Dynamics.Ax.Xpp

Assembly:

Microsoft.Dynamics.AX.Xpp.Support.dll

Calculates and retrieves the union of two given sets. This is the set that contains the values found in at least one of the sets.

public:
 static Microsoft::Dynamics::Ax::Xpp::Set ^ union(Microsoft::Dynamics::Ax::Xpp::Set ^ _set1, Microsoft::Dynamics::Ax::Xpp::Set ^ _set2);

public static Microsoft.Dynamics.Ax.Xpp.Set union (Microsoft.Dynamics.Ax.Xpp.Set _set1, Microsoft.Dynamics.Ax.Xpp.Set _set2);

static member union : Microsoft.Dynamics.Ax.Xpp.Set * Microsoft.Dynamics.Ax.Xpp.Set -> Microsoft.Dynamics.Ax.Xpp.Set

Public Shared Function union (_set1 As Set, _set2 As Set) As Set

Parameters

_set1

Set

The second of the two sets that are compared.

_set2

Set

The second of the two sets that are compared.

Returns

Set

The set containing elements found in set1 or set2.

Remarks

The two sets that are compared must be of the same type.

The following example creates two sets of integers and adds some values to them. It then creates a new set that contains all the values that are contained in either of the sets.

{ 
    Set is = new Set (Types::Integer); 
    Set is2, is1 = new Set (Types::Integer); 
    ; 
    is.add(1); 
    is.add(2); 
    is.add(3); 
    is1.add(2); 
    is1.add(4); 
    is2 = Set::union(is, is1); 
    // Prints "{1, 2, 3, 4}". 
    print is2.toString(); 
    pause; 
}