How to: Specify the Degree of Parallelism in a Dataflow Block
This document describes how to set the ExecutionDataflowBlockOptions.MaxDegreeOfParallelism property to enable an execution dataflow block to process more than one message at a time. Doing this is useful when you have a dataflow block that performs a long-running computation and can benefit from processing messages in parallel. This example uses the System.Threading.Tasks.Dataflow.ActionBlock<TInput> class to perform multiple dataflow operations concurrently; however, you can specify the maximum degree of parallelism in any of the predefined execution block types that the TPL Dataflow Library provides, ActionBlock<TInput>, System.Threading.Tasks.Dataflow.TransformBlock<TInput,TOutput>, and System.Threading.Tasks.Dataflow.TransformManyBlock<TInput,TOutput>.
Note
The TPL Dataflow Library (the System.Threading.Tasks.Dataflow namespace) is not distributed with .NET. To install the System.Threading.Tasks.Dataflow namespace in Visual Studio, open your project, choose Manage NuGet Packages from the Project menu, and search online for the System.Threading.Tasks.Dataflow package. Alternatively, to install it using the .NET Core CLI, run dotnet add package System.Threading.Tasks.Dataflow.
Example
The following example performs two dataflow computations and prints the elapsed time that is required for each computation. The first computation specifies a maximum degree of parallelism of 1, which is the default. A maximum degree of parallelism of 1 causes the dataflow block to process messages serially. The second computation resembles the first, except that it specifies a maximum degree of parallelism that is equal to the number of available processors. This enables the dataflow block to perform multiple operations in parallel.
using System;
using System.Diagnostics;
using System.Threading;
using System.Threading.Tasks.Dataflow;
// Demonstrates how to specify the maximum degree of parallelism
// when using dataflow.
class Program
{
// Performs several computations by using dataflow and returns the elapsed
// time required to perform the computations.
static TimeSpan TimeDataflowComputations(int maxDegreeOfParallelism,
int messageCount)
{
// Create an ActionBlock<int> that performs some work.
var workerBlock = new ActionBlock<int>(
// Simulate work by suspending the current thread.
millisecondsTimeout => Thread.Sleep(millisecondsTimeout),
// Specify a maximum degree of parallelism.
new ExecutionDataflowBlockOptions
{
MaxDegreeOfParallelism = maxDegreeOfParallelism
});
// Compute the time that it takes for several messages to
// flow through the dataflow block.
Stopwatch stopwatch = new Stopwatch();
stopwatch.Start();
for (int i = 0; i < messageCount; i++)
{
workerBlock.Post(1000);
}
workerBlock.Complete();
// Wait for all messages to propagate through the network.
workerBlock.Completion.Wait();
// Stop the timer and return the elapsed number of milliseconds.
stopwatch.Stop();
return stopwatch.Elapsed;
}
static void Main(string[] args)
{
int processorCount = Environment.ProcessorCount;
int messageCount = processorCount;
// Print the number of processors on this computer.
Console.WriteLine("Processor count = {0}.", processorCount);
TimeSpan elapsed;
// Perform two dataflow computations and print the elapsed
// time required for each.
// This call specifies a maximum degree of parallelism of 1.
// This causes the dataflow block to process messages serially.
elapsed = TimeDataflowComputations(1, messageCount);
Console.WriteLine("Degree of parallelism = {0}; message count = {1}; " +
"elapsed time = {2}ms.", 1, messageCount, (int)elapsed.TotalMilliseconds);
// Perform the computations again. This time, specify the number of
// processors as the maximum degree of parallelism. This causes
// multiple messages to be processed in parallel.
elapsed = TimeDataflowComputations(processorCount, messageCount);
Console.WriteLine("Degree of parallelism = {0}; message count = {1}; " +
"elapsed time = {2}ms.", processorCount, messageCount, (int)elapsed.TotalMilliseconds);
}
}
/* Sample output:
Processor count = 4.
Degree of parallelism = 1; message count = 4; elapsed time = 4032ms.
Degree of parallelism = 4; message count = 4; elapsed time = 1001ms.
*/
Imports System.Diagnostics
Imports System.Threading
Imports System.Threading.Tasks.Dataflow
' Demonstrates how to specify the maximum degree of parallelism
' when using dataflow.
Friend Class Program
' Performs several computations by using dataflow and returns the elapsed
' time required to perform the computations.
Private Shared Function TimeDataflowComputations(ByVal maxDegreeOfParallelism As Integer, ByVal messageCount As Integer) As TimeSpan
' Create an ActionBlock<int> that performs some work.
Dim workerBlock = New ActionBlock(Of Integer)(Function(millisecondsTimeout) Pause(millisecondsTimeout), New ExecutionDataflowBlockOptions() With {.MaxDegreeOfParallelism = maxDegreeOfParallelism})
' Simulate work by suspending the current thread.
' Specify a maximum degree of parallelism.
' Compute the time that it takes for several messages to
' flow through the dataflow block.
Dim stopwatch As New Stopwatch()
stopwatch.Start()
For i As Integer = 0 To messageCount - 1
workerBlock.Post(1000)
Next i
workerBlock.Complete()
' Wait for all messages to propagate through the network.
workerBlock.Completion.Wait()
' Stop the timer and return the elapsed number of milliseconds.
stopwatch.Stop()
Return stopwatch.Elapsed
End Function
Private Shared Function Pause(ByVal obj As Object)
Thread.Sleep(obj)
Return Nothing
End Function
Shared Sub Main(ByVal args() As String)
Dim processorCount As Integer = Environment.ProcessorCount
Dim messageCount As Integer = processorCount
' Print the number of processors on this computer.
Console.WriteLine("Processor count = {0}.", processorCount)
Dim elapsed As TimeSpan
' Perform two dataflow computations and print the elapsed
' time required for each.
' This call specifies a maximum degree of parallelism of 1.
' This causes the dataflow block to process messages serially.
elapsed = TimeDataflowComputations(1, messageCount)
Console.WriteLine("Degree of parallelism = {0}; message count = {1}; " & "elapsed time = {2}ms.", 1, messageCount, CInt(Fix(elapsed.TotalMilliseconds)))
' Perform the computations again. This time, specify the number of
' processors as the maximum degree of parallelism. This causes
' multiple messages to be processed in parallel.
elapsed = TimeDataflowComputations(processorCount, messageCount)
Console.WriteLine("Degree of parallelism = {0}; message count = {1}; " & "elapsed time = {2}ms.", processorCount, messageCount, CInt(Fix(elapsed.TotalMilliseconds)))
End Sub
End Class
' Sample output:
'Processor count = 4.
'Degree of parallelism = 1; message count = 4; elapsed time = 4032ms.
'Degree of parallelism = 4; message count = 4; elapsed time = 1001ms.
'
Robust Programming
By default, each predefined dataflow block propagates out messages in the order in which the messages are received. Although multiple messages are processed simultaneously when you specify a maximum degree of parallelism that is greater than 1, they are still propagated out in the order in which they are received.
Because the MaxDegreeOfParallelism property represents the maximum degree of parallelism, the dataflow block might execute with a lesser degree of parallelism than you specify. The dataflow block can use a lesser degree of parallelism to meet its functional requirements or to account for a lack of available system resources. A dataflow block never chooses a greater degree of parallelism than you specify.
