Grammar.IsStg Property

Definition

Namespace:

System.Speech.Recognition

Assembly:

System.Speech.dll

Package:

System.Speech v9.0.0

Source:

Grammar.cs

Gets whether a grammar is strongly typed.

protected public:
 virtual property bool IsStg { bool get(); };

protected internal virtual bool IsStg { get; }

member this.IsStg : bool

Protected Friend Overridable ReadOnly Property IsStg As Boolean

Property Value

Boolean

The IsStg property returns true if the grammar is strongly-typed; otherwise the property returns false.

Remarks

A strongly-typed Grammar object (IsStg equals true) can return strongly-typed results (objects, rather than raw text) to a client application. For example, a strongly-typed grammar might return DateTime objects rather than raw recognized input.

You can implement strongly-typed grammars by attaching code to the rules of a grammar. As a recognition engine processes any given rule, taking as input the current partial results, the associated code is executed and the textual information becomes rich type objects. This allows a client to more easily make use of enhanced semantic checking, support for multiple cultures, and internal grammar logic.

Instances of strongly-typed Grammar objects are typically obtained from resources in an assembly as a Type of the Common Language Runtime (CLR). The localized types used to support different languages are examples of such Grammar objects.

Notes to Inheritors

Strongly-typed grammars inheriting from Grammar need to override the default behavior of IsStg, which is to return false.