Expression.Default(Type) Method

Definition

Namespace:

System.Linq.Expressions

Assembly:

System.Linq.Expressions.dll

Source:

DefaultExpression.cs

Creates a DefaultExpression that has the Type property set to the specified type.

public:
 static System::Linq::Expressions::DefaultExpression ^ Default(Type ^ type);

public static System.Linq.Expressions.DefaultExpression Default (Type type);

static member Default : Type -> System.Linq.Expressions.DefaultExpression

Public Shared Function Default (type As Type) As DefaultExpression

Parameters

type

Type

A Type to set the Type property equal to.

Returns

DefaultExpression

A DefaultExpression that has the NodeType property equal to Default and the Type property set to the specified type.

Examples

The following code example shows how to create an expression that represents a default value for a given type.

// Add the following directive to your file:
// using System.Linq.Expressions;

// This expression represents the default value of a type
// (0 for integer, null for a string, etc.)
Expression defaultExpr = Expression.Default(
                            typeof(byte)
                        );

// Print out the expression.
Console.WriteLine(defaultExpr.ToString());

// The following statement first creates an expression tree,
// then compiles it, and then executes it.
Console.WriteLine(
    Expression.Lambda<Func<byte>>(defaultExpr).Compile()());

// This code example produces the following output:
//
// default(Byte)
// 0

' Add the following directive to your file:
' Imports System.Linq.Expressions  

' This expression represents the default value of a type
' (0 for integer, null for a string, and so on).
Dim defaultExpr As Expression = Expression.Default(
                                        GetType(Byte)
                                    )

' Print the expression.
Console.WriteLine(defaultExpr.ToString())

' The following statement first creates an expression tree,
' then compiles it, and then executes it.
Console.WriteLine(
    Expression.Lambda(Of Func(Of Byte))(defaultExpr).Compile()())

' This code example produces the following output:
'
' default(Byte)
' 0