Example: Mail-enabled User
This example shows how to provision an Exchange 2000 or Exchange 2003 mail-enabled user. The example assumes that you are using the Active Directory Connector (ADC) to maintain interoperability between Exchange 5.5 and Active Directory.
Attribute Inclusion List
You must select the following attributes from the Select Attributes property page for your Active Directory management agent to provision an Exchange mail-enabled user:
- mailNickname
- targetAddress
- legacyExchangeDN (If you are supporting a mixed Exchange environment. See Creating a Mail-Enabled User in a Mixed Exchange Environment, below.)
Creating a Mail-enabled User in a Homogeneous Exchange Environment
The following example shows how to use a rules extension to provision an Exchange mail-enabled user. Be sure to add a reference to logging.dll to use the LogException method.
Public Sub Provision(ByVal mventry As MVEntry) _
Implements IMVSynchronization.Provision
Dim adMA As ConnectedMA
Dim csentry As CSEntry
Dim nickName, targetAddress As String
Dim dn as ReferenceValue
Dim isExch2003 As Boolean
isExch2003 = false ' Exchange 2000 server
try
adMA = mventry.ConnectedMAs("Fabrikam AD MA")
nickName = mventry("mailNickname").Value
targetAddress = mventry("targetAddress").Value
' Construct the distinguished name
dn = adMA.EscapeDNComponent("CN=" + mventry("cn").Value).Concat("ou=mailboxes,dc=fabrikam,dc=com")
If 0 = adMA.Connectors.Count then
csentry = ExchangeUtils.CreateMailEnabledUser(adMA, dn, nickName, targetAddress, isExch2003)
End If
' Log and rethrow any exception
Catch ex As Exception
Logging.Logging.LogException(ex, "Provision", "Caught exception", False)
Throw
End Try
End Sub
void IMVSynchronization.Provision (MVEntry mventry)
{
ConnectedMA adMA;
CSEntry csentry;
String nickName, targetAddress;
ReferenceValue dn;
Boolean isExch2003;
isExch2003 = false; // Exchange 2000 server
try
{
adMA = mventry.ConnectedMAs["Fabrikam AD MA"];
nickName = mventry["mailNickname"].Value;
targetAddress = mventry["targetAddress"].Value;
// Construct the distinguished name
dn = adMA.EscapeDNComponent("CN=" + mventry["cn"].Value).Concat("ou=mailboxes,dc=fabrikam,dc=com");
if(0 == adMA.Connectors.Count)
{
csentry = ExchangeUtils.CreateMailEnabledUser(adMA, dn, nickName, targetAddress, isExch2003);
}
}
// Log and rethrow any exception
catch(Exception ex)
{
Logging.Logging.LogException(ex, "Provision", "Caught exception", false);
throw;
}
}
Creating a Mail-enabled User in a Mixed Exchange Environment
If your environment includes a mixed configuration of Exchange 5.5 and Exchange 2000 or Exchange 2003 servers and you are using the Active Directory connector to synchronize with Exchange 5.5, you must perform an additional step after you have called the CreateMailEnabledUser() method in your provisioning process: You must update the legacyExchangeDN connector to an Administrative Group to which a connection agreement of the Active Directory connector points.
The following example shows how to use a rules extension to provision an Exchange mail-enabled user in a mixed Exchange environment. Be sure to add a reference to logging.dll to use the LogException method.
Public Sub Provision(ByVal mventry As MVEntry) _
Implements IMVSynchronization.Provision
Dim adMA As ConnectedMA
Dim csentry As CSEntry
Dim nickName, targetAddress, rdnWithoutType, rdn, adminGroup As String
Dim dn as ReferenceValue
Dim equalSignInRDN As Integer
Dim isExch2003 As Boolean = false ' Exchange 2000 server
try
adMA = mventry.ConnectedMAs("Fabrikam AD MA")
nickName = mventry("mailNickname").Value
targetAddress = mventry("targetAddress").Value
' Construct the distinguished name
dn = adMA.EscapeDNComponent("CN=" + mventry("cn").Value).Concat("ou=mailboxes,dc=fabrikam,dc=com")
If 0 = adMA.Connectors.Count then
csentry = ExchangeUtils.CreateMailEnabledUser(adMA, dn, nickName, targetAddress, isExch2003)
equalSignInRDN = csentry.RDN.ToString().IndexOf("=")
rdnWithoutType = csentry.RDN.Substring(equalSignInRDN + 1)
rdn = "cn=" + rdnWithoutType + "-" + System.Guid.NewGuid().ToString()
adminGroup = "CN=First Administrative Group,CN=Administrative Groups,CN=Fabrikam,CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=fabrikam,DC=com"
csentry("legacyExchangeDN").Value = adminGroup + "/" + rdn
End If
' Log and rethrow any exception
Catch ex As Exception
Logging.Logging.LogException(ex, "Provision", "Caught exception", False)
Throw
End Try
End Sub
void IMVSynchronization.Provision (MVEntry mventry)
{
ConnectedMA adMA;
CSEntry csentry;
String nickName, targetAddress, rdnWithoutType, rdn, adminGroup;
ReferenceValue dn;
int equalSignInRDN;
Boolean isExch2003 = false; // Exchange 2000 server
try
{
adMA = mventry.ConnectedMAs["Fabrikam AD MA"];
nickName = mventry["mailNickname"].Value;
targetAddress = mventry["targetAddress"].Value;
// Construct the distinguished name
dn = adMA.EscapeDNComponent("CN=" + mventry["cn"].Value).Concat("ou=mailboxes,dc=fabrikam,dc=com");
if(0 == adMA.Connectors.Count)
{
csentry = ExchangeUtils.CreateMailEnabledUser(adMA, dn, nickName, targetAddress, isExch2003);
equalSignInRDN = csentry.RDN.ToString().IndexOf("=");
rdnWithoutType = csentry.RDN.Substring(equalSignInRDN + 1);
rdn = "cn=" + rdnWithoutType + "-" + System.Guid.NewGuid().ToString();
adminGroup = "CN=First Administrative Group,CN=Administrative Groups,CN=Fabrikam,CN=Microsoft Exchange,CN=Services,CN=Configuration,DC=fabrikam,DC=com";
csentry["legacyExchangeDN"].Value = adminGroup + "/" + rdn;
}
}
// Log and rethrow any exception
catch(Exception ex)
{
Logging.Logging.LogException(ex, "Provision", "Caught exception", false);
throw;
}
}
See Also
CreateMailEnabledUser(ConnectedMA,ReferenceValue,String,String,Boolean)
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Build date: 2/16/2009