operator!= (unordered_map)
Tests whether the unordered_map object on the left side of the operator is not equal to the unordered_map object on the right side.
bool operator!=(
const unordered_map <Key, Type, Hash, Pred, Allocator>& _Left,
const unordered_map <Key, Type, Hash, Pred, Allocator>& _Right
);
Parameters
_Left
An object of type unordered_map._Right
An object of type unordered_map.
Return Value
true if the unordered_maps are not equal; false if they are equal.
Remarks
The comparison between unordered_map objects is not affected by the arbitrary order in which they store their elements. Two unordered_maps are equal if they have the same number of elements and the elements in one container are a permutation of the elements in the other container. Otherwise, they are unequal.
Example
// unordered_map_op_ne.cpp
// compile by using: cl.exe /EHsc /nologo /W4 /MTd
#include <unordered_map>
#include <iostream>
#include <ios>
int main( )
{
using namespace std;
unordered_map<int, int> um1, um2, um3;
for ( int i = 0 ; i < 3 ; ++i ) {
um1.insert( make_pair( i+1, i ) );
um1.insert( make_pair( i, i ) );
um2.insert( make_pair( i, i+1 ) );
um2.insert( make_pair( i, i ) );
um3.insert( make_pair( i, i ) );
um3.insert( make_pair( i+1, i ) );
}
cout << boolalpha;
cout << "um1 != um2: " << (um1 != um2) << endl;
cout << "um1 != um3: " << (um1 != um3) << endl;
cout << "um2 != um3: " << (um2 != um3) << endl;
}
Output:
um1 != um2: true
um1 != um3: false
um2 != um3: true
Requirements
Header: <unordered_map>
Namespace: std