isgraph

Testet, ob ein Element in einem Gebietsschema ein alphanumerisches oder Satzzeichen ist.

template<Class CharType> 
   bool isgraph( 
      CharType _Ch,  
      const locale& _Loc 
   )

Parameter

• _Ch
  Das zu testenden Element.

• _Loc
  Das Gebietsschema, das das zu testenden Element enthält.

Rückgabewert

true, wenn das getestete Element ein alphanumerisches ist oder ein Interpunktionszeichen; false, wenn nicht.

Hinweise

Die Vorlagenfunktion gibt use_facet<C<CharType zurück > >(_Loc).ist(::<ctype>CharTypegraph, _Ch).

Beispiel

// locale_is_graph.cpp
// compile with: /EHsc
#include <locale>
#include <iostream>

using namespace std;

int main( )
{
   locale loc ( "German_Germany" );
   bool result1 = isgraph ( 'L', loc );
   bool result2 = isgraph ( '\t', loc );
   bool result3 = isgraph ( '.', loc );

   if ( result1 )
      cout << "The character 'L' in the locale is\n "
           << "an alphanumeric or punctuation character." << endl;
   else
      cout << "The character 'L' in the locale is\n "
           << " not an alphanumeric or punctuation character." << endl;

   if ( result2 )
      cout << "The character 'backslash-t' in the locale is\n "
           << "an alphanumeric or punctuation character." << endl;
   else
      cout << "The character 'backslash-t' in the locale is\n "
           << "not an alphanumeric or punctuation character." << endl;

   if ( result3 )
      cout << "The character '.' in the locale is\n "
           << "an alphanumeric or punctuation character." << endl;
   else
      cout << "The character '.' in the locale is\n "
           << " not an alphanumeric or punctuation character." << endl;
}

Ausgabe

The character 'L' in the locale is
 an alphanumeric or punctuation character.
The character 'backslash-t' in the locale is
 not an alphanumeric or punctuation character.
The character '.' in the locale is
 an alphanumeric or punctuation character.

Anforderungen

Gebietsschema Header: <>

Namespace: std