Freigeben über

SQL Server Function to get the Hour of the Year

  • Artikel

This function returns an integer of the hour of the year passed as a variable.

 IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[util].[uf_GetHourOfYear]') 

 AND type IN (N'FN', N'IF', N'TF', N'FS', N'FT'))

 DROP FUNCTION [util].[uf_GetHourOfYear]

 GO

 CREATE FUNCTION [util].[uf_GetHourOfYear](

  @date DATETIME

 )

 RETURNS INTEGER

 WITH EXECUTE AS CALLER

 AS

 /**********************************************************************************************************

 * UDF Name: 

 * [util].[uf_GetHourOfYear]

 * Parameters: 

 * @date datetime - The date to convert

 * Purpose: This function returns an integer of the hour of the year passed as a variable.

 *

 * Example:

  select [util].[uf_GetHourOfYear](GETDATE())

 * 

 * Revision Date/Time:

 * August 1, 2007

 *

 **********************************************************************************************************/

 BEGIN

  -- declare variables

  DECLARE @result integer;

  

  SET @result = (DATEPART(dy,@DATE) - 1) * 24 + DATEPART(hh,@DATE);

  -- return results.

  RETURN @result;

  

 END;

 GO

 SELECT [util].[uf_GetHourOfYear](GETDATE());

 GO

Technorati Tags:
SQL SERVER
,
SQL
,
YUKON
,
KATMAI
,
DateTime Function
,
User defined function

Comments